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0.4x^2=0.42x
We move all terms to the left:
0.4x^2-(0.42x)=0
We add all the numbers together, and all the variables
0.4x^2-(+0.42x)=0
We get rid of parentheses
0.4x^2-0.42x=0
a = 0.4; b = -0.42; c = 0;
Δ = b2-4ac
Δ = -0.422-4·0.4·0
Δ = 0.1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.42)-\sqrt{0.1764}}{2*0.4}=\frac{0.42-\sqrt{0.1764}}{0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.42)+\sqrt{0.1764}}{2*0.4}=\frac{0.42+\sqrt{0.1764}}{0.8} $
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